a^2+(10/7)a+(25/49)=0

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Solution for a^2+(10/7)a+(25/49)=0 equation: 


a in (-oo:+oo)

a^2+(10/7)*a+25/49 = 0

a^2+10/7*a+25/49 = 0

DELTA = (10/7)^2-(25/49*1*4)

DELTA = 0

a = -10/7/(1*2)

a = -5/7 or a = -5/7

a in { -5/7, -5/7 }

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